예제 풀이 사전 정보 (홀짝찾기)
## Odd or Even
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# Instructions
Write a program that works out whether if a given number is an odd or even number.
Even numbers can be divided by 2 with no remainder.
e.g. 86 is **even** because 86 ÷ 2 = 43
43 does not have any decimal places. Therefore the division is clean.
e.g. 59 is **odd** because 59 ÷ 2 = 29.5
29.5 is not a whole number, it has decimal places. Therefore there is a remainder of 0.5, so the division is not clean.
The **modulo** is written as a percentage sign (%) in Python. It gives you the remainder after a division.
e.g.
6 ÷ 2 = 3 with no remainder.
```
6 % 2 = 0
```
5 ÷ 2 = 2 x **2** + 1, remainder is 1.
```
5 % 2 = 1
```
14 ÷ 4 = 3 x **4** + 2, remainder is 2.
```
14 % 4 = 2
```
**Warning** your output should match the Example Output format exactly, even the positions of the commas and full stops.
# Example Input 1
```
43
```
# Example Output 1
```
This is an odd number.
```
# Example Input 2
```
94
```
# Example Output 2
```
This is an even number.
```
e.g. When you hit **run**, this is what should happen:
# Hint
1. All even numbers can be divided by 2 with 0 remainder.
2. Try some using the modulo with some odd numbers e.g.
```
3 % 2
```
```
5 % 2
```
```
7 % 2
```
Then try using the modulo with some even numbers e.g.
```
4 % 2
```
```
6 % 2
```
```
8 % 2
```
See what's in common each time.혼자 풀이
# 🚨 Don't change the code below 👇
number = int(input("Which number do you want to check? "))
# 🚨 Don't change the code above 👆
#Write your code below this line 👇
if number % 2 == 1:
print("This is an odd number.")
elif number % 2 == 0 :
print("This is an even number")
else:
print("error!")개선 : 정수는 2로 나누면 나머지가 0이나 1밖에 없어서 elif 까지 사용할 필요가 없었다. 간결한 코드 작성을 한다면
# 🚨 Don't change the code below 👇
number = int(input("Which number do you want to check? "))
# 🚨 Don't change the code above 👆
#Write your code below this line 👇
if number % 2 == 1:
print("This is an odd number.")
else:
print("This is an even number")
